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Posted by DrZot on November 23, 2002 at 08:38:22:
In Reply to: Re: This ought to be interesting... posted by bazmonkey on November 23, 2002 at 00:29:02:
Methinks you're using the wrong Punnett :) For two traits (assuming not linked) the results of crossing two double heterozygotes (carriers of both traits) will result in a 9:3:3:1 ratio of offspring appearances. 9 look normal (includes carriers of each trait), 3 express one of the recessives (anerythrism), 3 the other recessive (melanism), and 1 is double recessive (whatever that looks like!). Statistically out of 16 offspring, of course.
:If it's a recessive trait like it is in cornsnakes, you're going to get completely normal offspring, all of which are het for melanism and erythrism. If you breed these offspring, a quarter will be melanistic (half of which are het for erythrism), a quarter erythristic (half of which are het for melanism), a quarter normal (with a quarter of them het for erythrism, a quarter het for melanism, a quarter het for none, and a quarter double het for both), and a quarter of them will come out with both traits expressed, if both can be expressed in one animal.
:Hope that's not entirely confusing.
:An easier way would be to take one of the offspring, mate it with one of the original parents, and half of those kids should be showing the trait the parent was (depending on which parent you bred with). If you do that then there's a 50/50 chance one of those showing the traits are het for the other trait.
:It's all a matter of breeding them with the best statistical chances of getting what you want.
:Short answer: you'll have a bunch of normal offspring in the first generation that will make interesting babies together. Bust out a piece of paper, and you can figure out how to genetically guarantee a way to breed the traits together.
:I'm guessing bloody red is what they'll look like, but I probably won't be on this forum in the 4 years it'd take to figure out.
:Genetics are fun!
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